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public:t-622-arti-13-1:lab_5_-_bayesian_networks [2013/03/15 10:17] – [Material] stephanpublic:t-622-arti-13-1:lab_5_-_bayesian_networks [2024/04/29 13:33] (current) – external edit 127.0.0.1
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   * <latex>$P(\neg A) = 1 - P(A)$</latex>   * <latex>$P(\neg A) = 1 - P(A)$</latex>
   * Bayes Law: <latex>$P(A \land B) = P(A|B) * P(B)$</latex>   * Bayes Law: <latex>$P(A \land B) = P(A|B) * P(B)$</latex>
-  * Marginalization/Summing out: <latex>$P(A) = \sum_b P(A \land b) = P(A \land A) + P(A \land \neg B)$</latex>+  * Marginalization/Summing out: <latex>$P(A) = \sum_b P(A \land b) = P(A \land B) + P(A \land \neg B)$</latex>
   * Independence 1: <latex>$P(A|B,C) = P(A|C)$</latex>, if <latex>$A$</latex> and <latex>$B$</latex> are independent given <latex>$C$</latex>.   * Independence 1: <latex>$P(A|B,C) = P(A|C)$</latex>, if <latex>$A$</latex> and <latex>$B$</latex> are independent given <latex>$C$</latex>.
   * Independence 2: <latex>$P(A \land B|C) = P(A|C) * P(B|C)$</latex>, if <latex>$A$</latex> and <latex>$B$</latex> are independent given <latex>$C$</latex>. (This follows from Independence 1 and Bayes Law.)   * Independence 2: <latex>$P(A \land B|C) = P(A|C) * P(B|C)$</latex>, if <latex>$A$</latex> and <latex>$B$</latex> are independent given <latex>$C$</latex>. (This follows from Independence 1 and Bayes Law.)
/var/www/cadia.ru.is/wiki/data/attic/public/t-622-arti-13-1/lab_5_-_bayesian_networks.1363342644.txt.gz · Last modified: 2024/04/29 13:32 (external edit)

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